How many calories are in a 12 0z Bud Light?

Answered by Daniel Conrad

A 12-ounce can of Bud Light contains approximately 110 calories. This information is important for those who are conscious about their calorie intake, especially if they are following a “New Year, new you” diet. It's interesting to note that the calories in Bud Light come primarily from carbohydrates, with a small percentage coming from protein.

For individuals who are watching their calorie intake, it's helpful to know that a 12-ounce can of Bud Light accounts for about 5.5% of the average daily calorie intake for an adult on a 2,000-calorie diet. This can be a useful reference point for individuals who are tracking their calories and trying to maintain a balanced diet.

In terms of macronutrients, a 12-ounce can of Bud Light contains approximately 2% of the recommended daily value of carbohydrates and less than 1% of protein. While the carbohydrate content is relatively low, it's worth noting that it still contributes to the overall calorie count. It's always important to be aware of the total calorie intake, regardless of the macronutrient breakdown.

As a sommelier and brewer, I understand the importance of knowing the nutritional information of different beverages. While Bud Light may not have a complex flavor profile or be as rich in nutrients as other beverages, it can still be enjoyed in moderation as part of a balanced .

It's worth mentioning that personal preferences and individual dietary needs may vary. It's always a good idea to consult with a healthcare professional or registered dietitian for personalized advice on calorie intake and dietary choices.

To summarize, a 12-ounce can of Bud Light contains approximately 110 calories, with the majority coming from carbohydrates and a small percentage from protein. This information can be helpful for individuals who are monitoring their calorie intake and trying to make informed choices about their dietary habits. Remember, moderation is key when enjoying any as part of a healthy lifestyle.